Let's model the problem like a circle.
The circumference of a circle is given by:
[tex]C = 2 \pi r[/tex]
Where,
r: radius of the circle.
Clearing the radius we have:
[tex]r = \frac{C}{2\pi }[/tex]
Then, replacing values we have:
[tex]r = \frac{25}{2\pi }[/tex]
[tex]r = 3.98 inches[/tex]
Answer:
The best approximation for the radius of the tin is:
[tex]r = 3.98 inches[/tex]
