We see that terms in given sequence increases by 9 continuously so that means this is an arithmetic progression (AP)
so we will use nth term formula of AP to find the a14
a_n=a_1+(n-1)d
n=14 because we need a14
a1= first term = 2
d = common difference = 11-2=9
Now plug these values into formula [tex] a_n=a_1+(n-1)d [/tex]
[tex]a_{14}=2+(14-1)(9) [/tex]
[tex]a_{14}=2+(13)(9) [/tex]
[tex]a_{14}=2+117 [/tex]
[tex]a_{14}=119 [/tex]
So the final answer is [tex] a_{14}=119 [/tex]
