GavinWright3876 GavinWright3876
  • 31-07-2018
  • Physics
contestada

If net force of 25 n is exerted over distance of m to the right on 2 kg mass initially at rest and moved it what is final velocity

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AL2006
AL2006 AL2006
  • 31-07-2018

The work done on the mass is (force) · (distance) = 25·m joules.

That work shows up as kinetic energy of the mass = (1/2)·(mass)·(speed)² .

(1/2)·(mass)·(speed²) = 25m joules

(1 kg)·(speed²) = 25m joules

speed² = (25m joules) / (1 kg) = 25m meters²/sec²

speed = 5·√m meters/sec

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