Respuesta :

[tex] \bf \begin{cases}
\boxed{m}=5n-3\\
m=3n+7
\end{cases}\implies \boxed{5n-3}=3n+7\implies 2n=10
\\\\\\
n=\cfrac{10}{2}\implies n=5 [/tex]

sqdancefan

Subtract the second equation from the first.

... 0 = 2n -10

Divide by the coefficient of n.

... 0 = n - 5

Add 5.

... 5 = n . . . . the lower-left selection is appropriate

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