19davislink 19davislink
  • 01-07-2018
  • Mathematics
contestada

Evaluate g(n-7) if g(x)= x^2-5/3x
A. n^2-14n+44/3n-7
B. (n^2-5/3n)-7
C. n^2-14n+44/3n-21
D. n^2-7/3n-63

Respuesta :

frika
frika frika
  • 02-07-2018
You have function [tex]g(x)=x^2- \frac{5}{3} x[/tex]. To count [tex]g(n-7)[/tex] you have to substitute [tex]n-7[/tex] instead of x in the expression of g(x):
[tex]g(n-7)=(n-7)^2- \frac{5}{3} (n-7)=n^2-14n+49- \frac{5}{3} n+ \frac{5}{3} \cdot 7=[/tex]
[tex]=n^2+n(-14- \frac{5}{3} )+(49+\frac{35}{3} )=n^2- \frac{47}{3} n+ \frac{182}{3} [/tex].
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