Answer
Part 1 = -441
Part 2 = -539
Explanation
(p.q)(5) = (-2x+1)(2x²-1)
= (-2x×2x²)-(-2x×1)+(1×2x²)-(1×1)
= -4x³+2x+2x²-1
= -4x³+2x²+2x-1
Substituting x witj 5;
-4×5³+2×5²+2×5-1
-441
part 2
(q.p)(5) = (2x²-1)(-2x+1)
= (2x²×-2x)-(2x²×1)-(1×-2x)+(1×1)
= -4x³-2x²+2x+1
Substituting x with 5;
-4×5³-2×5²+2×5+1
-539
