Respuesta :

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[tex]f(x)=3x+1\\\\g(x)=\dfrac{4x+2}{4}\\\\f(0)=3\cdot0+1=0+1=1\\\\g(f(0))=g(1)=\dfrac{4\cdot1+2}{4}=\dfrac{4+2}{4}=\dfrac{6}{4}=\dfrac{6:2}{4:2}=\dfrac{3}{2}=1.5[/tex]

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