payshencec21
payshencec21
30-05-2018
Mathematics
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please help asap 25 pts
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gmany
gmany
30-05-2018
[tex]\dfrac{6x-24}{16-x^2}=\dfrac{6(x-4)}{4^2-x^2}=\dfrac{6(x-4)}{-(x^2-4^2)}\\\\=\dfrac{6(x-4)}{-(x-4)(x+4)}\\\\\boxed{Answer:\ -
\dfrac{6}{x+4}}[/tex]
[tex]Used:\ a^2-b^2=(a-b)(a+b)[/tex]
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