we have
[tex]\frac{6x-5}{2}=2x+6[/tex]step 1
Multiply by 2 both sides
[tex]\begin{gathered} 6x-5=2(2x+6) \\ 6x-5=4x+12 \end{gathered}[/tex]step 2
Group terms
[tex]6x-4x=12+5[/tex]Combine like terms
[tex]2x=17[/tex]divide by 2 both sides
[tex]\begin{gathered} x=\frac{17}{2} \\ x=8.5 \end{gathered}[/tex]Verify
substitute the value of x in the original expression
[tex]\begin{gathered} \frac{6(8.5)-5}{2}=2(8.5)+6 \\ 23=23 \end{gathered}[/tex]is ok
the value of x satisfy the equation
