+2. Option A is correct.
Given the compound FeSO₄, we are to get the charge on Iron(Fe). From the given compound;
• The o,xidation state ,of sulfur (S) is +6
,• Oxidation state of oxygen is -2(4) = -8
Let the oxidation state of iron (Fe) be "x"
Taking the sum of the oxidation state and equate to zero to get the value of "x"
[tex]x+6+(-8)=0[/tex]Simplify the result
[tex]\begin{gathered} x+6-8=0 \\ x-2=0 \\ x-2+2=0+2 \\ x=+2 \end{gathered}[/tex]This shows that the charge on iron in FeSO4 is +2
