EllagraceC298803 EllagraceC298803

29-10-2022
Chemistry

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When lead(II) nitrate reacts with sodium iodide, what is the correct formula for the product lead(II) iodide?Pb 2Pb22Pol4Pb214Pb2Hoo.

When leadII nitrate reacts with sodium iodide what is the correct formula for the product leadII iodidePb 2Pb22Pol4Pb214Pb2Hoo class=

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SuaW646629 SuaW646629

29-10-2022

Lead (II) nitrate = Pb(NO3)2

Sodium iodide = NaI

When they react:

Pb(NO3)2 + 2NaI => 2NaNO3 + PbI2

PbI2 is formed as a product. It is called lead (II) iodide

Answer: PbI2

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