Respuesta :

Given

[tex]\ln 2=3x+1[/tex]

Procedure

The natural log, or ln, is the inverse of e.

[tex]\begin{gathered} e^{\ln 2}=e^{3x+1} \\ 2=e^{3x+1} \end{gathered}[/tex]

The answer would be option B. 2 = e^(3x+1)

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