SOLUTION:
Case: Right-angle triangle
Method:
[tex]\begin{gathered} Using\text{ }the\text{ }rule:1-\sqrt{3}-2 \\ \sin(30\degree)=\frac{Opp}{Hyp} \\ Hyp=2(2.5) \\ Hyp=5 \\ sin(30\degree)=\frac{2.5}{50} \end{gathered}[/tex]
Final answer:
[tex]\begin{gathered} \\ sin(30\degree)=\frac{1}{2} \end{gathered}[/tex]
