To find the equation of the line that passes through point (6, -5) with a slope 5/2
we already know that slope m=5/2
so we will find the intercept
To find the intercept, substitute m = 5/2 x=6 and y=-5 into;
y=mx + b
and then solve for b
That is;
-5 = (5/2)(6) + b
-5 = 15 + b
subtract 15 from both-side of the equation
-5 - 15 = b
-20 = b
b= -20
To form the new equation, simply substitute m=5/2 and b=-20 into y=mx + b
That is;
y = (5/2) x - 20
Multiply through the equation by 2
2y = 5x - 40
Re-arrange;
5x - 2y = 40
