Respuesta :

aide035878

Answer:

Solution

verified

Verified by Toppr

The radius of the tire is r=0.500m. The speed of the stone on its outer edge is

  v  

t

​

=  

T

2πr

​

=  

(60.0s/200rev)

2π(0.500m)

​

=10.5m/s

and its acceleration is

  a=  

R

v  

2

 

​

=  

0.500m

(10.5m/s)  

2

 

​

=219m/s  

2

 inward.

Explanation:

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