Answer:
The inverse is -3 ±sqrt(5x+7/2)
Step-by-step explanation:
5y+4=(x+3)^2+1/2?
To find the inverse, exchange x and y
5x+4=(y+3)^2+1/2
Solve for y
Subtract 1/2
5x+4 -1/2=(y+3)^2+1/2-1/2
5x+8/2 -1/2=(y+3)^2+1/2-1/2
5x+7/2 = (y+3)^2
Take the square root of each side
±sqrt(5x+7/2) =sqrt( (y+3)^2)
±sqrt(5x+7/2) = (y+3)
Subtract 3 from each side
-3 ±sqrt(5x+7/2) = y+3-3
-3 ±sqrt(5x+7/2) = y
The inverse is -3 ±sqrt(5x+7/2)
