Answer:
Reduction:
2e- + 2k+ ➡️ 2k
2e- + pb2+ ➡️pb
2e- +2H+ ➡️H2(diatomic molecule)
Oxidation :
2cl- ➡️cl2 + 2e- (Cl is a diatomic molecule)
2O-2➡️ O2+4e- (also diatomic molecule)
2Br-➡️ Br2 + 2e- (Br is also a diatomic molecule)
I don't know if I answered ur question or not but I hope this would help
