tailadixon31 tailadixon31
  • 31-08-2020
  • Mathematics
contestada

What is the equation of a line that is perpendicular to y = -1/5x + 1 and passes through point (0, -2)?

Respuesta :

rococo908
rococo908 rococo908
  • 31-08-2020

Answer:

y = 5x - 2

Step-by-step explanation:

The slope will be 5, because that is the opposite reciprocal of the original slope, -1/5

Then, plug the slope and the given point into y = mx + b to find b:

y = mx + b

-2 = 5(0) + b

-2 = 0 + b

-2 = b

Then, plug the y-intercept and the slope into the equation:

y = 5x - 2 will be the equation

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