SlytherinPrincess8 SlytherinPrincess8
  • 30-05-2020
  • Mathematics
contestada

Please help!


Find the interval of convergence for:

Please note: The 2 in the picture must actually also be an exponent, so n^2^n.

Please help Find the interval of convergence for Please note The 2 in the picture must actually also be an exponent so n2n class=

Respuesta :

MathPhys
MathPhys MathPhys
  • 30-05-2020

Answer:

-∞ < x < ∞

Step-by-step explanation:

∑ xⁿ / n^(2ⁿ)

Apply ratio test:

lim(n→∞) | [xⁿ⁺¹ / (n+1)^(2ⁿ⁺¹)] / [xⁿ / n^(2ⁿ)] |

lim(n→∞) | [xⁿ⁺¹ / (n+1)^(2ⁿ⁺¹)] × [n^(2ⁿ) / xⁿ] |

lim(n→∞) | x n^(2ⁿ) / (n+1)^(2ⁿ⁺¹) |

0

The series converges for all values of x.

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