Answer:
r=-6
r=-1
Step-by-step explanation:
[tex]r^2+7r+6\\(r+6)(r+1)=0\\\\r+6=0\\r=-6\\\\r+1=0\\r=-1[/tex]
r = -6
or
r = -1
from your question
r² + 7r + 6 = 0
we have,
(r +6)(r + 1)
either
r + 6 =0
r + 1 = 0
