nazkahalmaida nazkahalmaida
  • 29-09-2019
  • Mathematics
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find 2 consecutive integers such that three times the square of the first is equal to seven more than five times the second

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corm
corm corm
  • 29-09-2019

Answer:

Step-by-step explanation:

We are looking for two numbers, [tex]N[/tex] and [tex]N + 1[/tex]. From the problem statement, we can setup the following equation:

[tex]3N^{2} = 5(N + 1) + 7[/tex]

[tex]3N^{2} = 5N + 5 + 7[/tex]

[tex]3N^{2} - 5N - 12 = 0[/tex]

[tex](3N + 4)(N - 3)[/tex]

[tex]N = \frac{-4}{3}, 3[/tex]

Because 3 is the only integer solution, the answer is 3 and 4.

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