Answer:
1109m
Explanation:
The distance h₁ traveled by the rocket during acceleration:
[tex]h_1=\frac{1}{2}at^2[/tex]
The velocity v₁ at this height h₁:
[tex]v_1=at[/tex]
When the rocket runs out of fuel, energy is conserved:
[tex]E=\frac{1}{2}mv_1^2+mgh_1=mgh_2[/tex]
Solving for h₂:
[tex]h_2=\frac{v_1^2}{2g}+h_1=\frac{(at)^2}{2g}+\frac{1}{2}at^2[/tex]
